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-0.03x^2+0.63x-2.4=0
a = -0.03; b = 0.63; c = -2.4;
Δ = b2-4ac
Δ = 0.632-4·(-0.03)·(-2.4)
Δ = 0.1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.63)-\sqrt{0.1089}}{2*-0.03}=\frac{-0.63-\sqrt{0.1089}}{-0.06} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.63)+\sqrt{0.1089}}{2*-0.03}=\frac{-0.63+\sqrt{0.1089}}{-0.06} $
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